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How to divide complex numbers
How to divide complex numbersIn this article, you will read how to divide complex numbers. To make complex number division, you need to do the following steps:
Example: \( \frac{1}{i} = ? \)We can simplify this expression by multiplying both the numerator and denominator by \(-i\), which gives: \[\frac{1}{i} = \frac{1}{i}\cdot\frac{i}{i} = \frac{i}{i^2} = \frac{i}{-1} = -i\] Therefore, the reciprocal of \(i\) is equal to \(i\). Example: \( \frac{1+i}{1-i} = ? \)To solve \((1+i)/(1-i)\), we can first multiply the numerator and denominator by the complex conjugate of the denominator: \[\begin{align*}\frac{1+i}{1-i} = \frac{(1+i)(1+i)}{(1-i)(1+i)} = \\ = \frac{1+2i+i^2}{1-i^2} = \frac{2i}{2} = i\end{align*}\] Therefore, \((1+i)/(1-i) = i\). Example: \( \frac{1}{a + bi} = ? \)The reciprocal of a complex number \(z=a+bi\) can be found by multiplying both the numerator and denominator of \(\frac{1}{a+bi}\) by the complex conjugate of the denominator, \(a-bi\). This gives: \[\frac{1}{a+bi} = \frac{1}{a+bi} \cdot \frac{a-bi}{a-bi} = \frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i\] Thus, the reciprocal of a complex number is equal to the complex conjugate of the denominator divided by the sum of the squares of the real and imaginary parts of the original complex number. Applying this formula to the specific case of \(1/(a+bi)\), we get: \[\frac{1}{a+bi} = \frac{a - bi}{a^2 + b^2} \]
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